Calculating Solenoid Turns: Magnetic Field, Current, and Dimensions

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(a) How many turns of wire would be on a solenoid carrying a current 4.9 A if the solenoid is 20 cm in diameter, 248 cm long, and the field at the center is 3.3 × 10-3 T?



The magnetic field of a solenoid is the permeability of free space times the number of turns per unit length times the current.



Now How do i find the Number of turns per unit length, Is it Length/Diameter * The field of Center? Thanks
and i know n = N/L so how do i find that

 

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Okay so Basically i tried to use N = 2RB/ (uoI) to get the answer but that does not work

 

[Chi Meson]

(a) How many turns of wire would be on a solenoid carrying a current 4.9 A if the solenoid is 20 cm in diameter, 248 cm long, and the field at the center is 3.3 × 10-3 T?



The magnetic field of a solenoid is the permeability of free space times the number of turns per unit length times the current.



Now How do i find the Number of turns per unit length, Is it Length/Diameter * The field of Center? Thanks
and i know n = N/L so how do i find that

The diameter of a long solenoid does not matter. The magnetic field (ideally) is B=(uo)nI . Solve for n .

 

[Alt+F4]

The diameter of a long solenoid does not matter. The magnetic field (ideally) is B=(uo)nI . Solve for n .

thanks a lot