Calculating Specific Charge (q/m) for a Charged Particle in a Magnetic Field

  • Thread starter Thread starter Britney2
  • Start date Start date
AI Thread Summary
To calculate the specific charge (q/m) of a charged particle moving in a magnetic field, the Lorentz force equation is applied, where the magnetic force provides the centripetal force necessary for circular motion. Given the particle's speed of v=8x10^7 m/s, magnetic field strength B=0.7 T, angle λ=45°, and radius R=4 cm, the relationship BQv sin(λ) = mv^2/R is utilized. By rearranging this equation, the specific charge can be derived. The angle affects the effective magnetic force, as sin(45°) equals √2/2, which must be considered in the calculations. Ultimately, this approach allows for the determination of the specific charge of the particle in the given conditions.
Britney2
Messages
3
Reaction score
0
A charged particle that moves with the speed v=8x10(7) goes in a magnetic field where B=0.7 T (B is the induction) and it makes an angle λ=45◦ with force lines. How is the specific charge(q/m) if the radius is R=4 cm?
(qvb=mv2/R qvb is the formula of the Lorenc force and mv2/R is the centripetal.)
 
Physics news on Phys.org
The force exerted on the charged particle at an angle \theta to a magnetic field of flux density,B, and moving with a velocity,v, provides the centripetal force to keep it moving a circular path.

So that

BQvsin\theta=\frac{mv^2}{r}

Which is the formula you posted in a sense...
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Struggle to understand the concept of the question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Circular trajectory traveled by a charged particle in a magnetic field
Replies
3
Views
2K
What is the induced magnetic force on this closed current loop?
Replies
12
Views
2K
Motion of a Charged Particle in Magnetic Field
Replies
2
Views
2K
Motion of a charged particle in magnetic field
Replies
11
Views
2K
Question on magnetism: Circular motion of charged particle in a Magnetic Field
Replies
34
Views
1K
A Charged Particle moving in Uniform Magnetic Field
Replies
2
Views
2K
Ball rolling in a magnetic field
Replies
2
Views
2K
Charged particle motion in a magnetic feild
Replies
8
Views
2K
Making sense of sequence of ideas in MIT OCW's 8.02 notes on Faraday
Replies
1
Views
1K
Particles in a Magnetic Field Question
Replies
13
Views
3K

Hot Threads

Recent Insights

Back
Top