Calculating spring constant of a spring loaded cannon

AI Thread Summary
To calculate the spring constant for a spring-loaded cannon that must launch a projectile over a 35 m high and 30 m wide building at a 60-degree angle, the minimum launch speed must first be determined. The initial calculations provided suggest a velocity of approximately 18.425 m/s, but further analysis is needed to ensure the projectile clears both the height and width of the building. The potential energy stored in the spring must equal the kinetic energy at launch, leading to the equation K = F / x, where F is the force and x is the spring compression. To accurately find the spring constant, the trajectory equations (SUVAT) should be applied to ensure the projectile's path meets the necessary clearance. The discussion emphasizes the importance of incorporating both the height and width of the building into the calculations for a successful launch.
alphaQ
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Homework Statement


if you wanted to build a spring launched cannon that will shoot you over a building that is 35 m high and 30 m wide, and the cannon is being shot at 60 degrees. If the cannon can be no more than 2 m long, what spring constant do you need in the spring to make this work? here is what I have been able to do, any feed back would be appreciated.

Homework Equations

^2= r/()
PE = KE
½ Fx = ½ mv^2
K = F / x

The Attempt at a Solution



to find the velocity I used:

v = sqrt((30* 9.8 m/s^2)/sin(60))
v = 18.425 m/s

Theoretically, humans can handle any velocity, it’s acceleration that we cannot handle well. A typical human can handle up to 5Gs of acceleration, that’s 49 ^2.

Since the maximum PE of the spring is the maximum KE of the mass PE = KE ½ Fx = ½ mv^2 Rearranging the formula, we get: = ^2/

F = ma = (70kg) (49m/s2) = 3430 N

KE = ½ mv2 = ½ (70kg) (18.425 m/s2) = 644.875 J

So, x = (644.875 J) / (½ ) (3430 N) x = 0.3760204082 m

We can now use x to solve for the spring constant

K = F / x

K = 3430N / 0.3760204082m + 2m(for the length of the cannon)

K = 1443.590294 N/m

is this K the right spring constant for this question?
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alphaQ said:
v = sqrt((30* 9.8 m/s^2)/sin(60))
Not so fast: the building has a height and a width. You must clear it completely.
Draw a diagram.
 
haruspex said:
Not so fast: the building has a height and a width. You must clear it completely.
Draw a diagram.
thats where i have the problem, i don't know how to incorporate the width and height into the equation
 
alphaQ said:
thats where i have the problem, i don't know how to incorporate the width and height into the equation
You are looking for the minimum energy, so only just clearing the building.
If the launch is at speed v and distance x from the building, what equations can you write for just clearing it?
(Take the launch speed as being at ground level.)
 
haruspex said:
You are looking for the minimum energy, so only just clearing the building.
If the launch is at speed v and distance x from the building, what equations can you write for just clearing it?
(Take the launch speed as being at ground level.)
i was thinking of getting the spring constant and then checking whether that constant would allow me to get over the height of the building
 
alphaQ said:
i was thinking of getting the spring constant and then checking whether that constant would allow me to get over the height of the building
To find the spring constant you need the launch energy, and to find that you need to find the minimum speed that will get you over the building. Start with solving the trajectory.
 
haruspex said:
To find the spring constant you need the launch energy, and to find that you need to find the minimum speed that will get you over the building. Start with solving the trajectory.
can you please give me an equation to get the launch energy?
 
alphaQ said:
can you please give me an equation to get the launch energy?
As I wrote, you need to start by finding the trajectory.
You did not quote any relevant equations for that. Do you know what I mean by SUVAT equations? If not, look them up.
 
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