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Calculating standing waves, given a fruequency? :O

  • Thread starter SFSKabam
  • Start date
1
0
1. Homework Statement
"Design a tube closed on one end so that it's lowest frequency standing wave is 440Hz. (i.e. determine the length of the tube."


2. Homework Equations
Um...I was unsure.
I thought maybe...I might use w=2(pi)f...and the function 2A sin (kx) cos (wt), but I epically failed on it.


3. The Attempt at a Solution
My solution was rather embarrassing, and it acquired me 0/10 points on my exam, thus I went online trying to get help (from Wiki and the sorts), then I found this site, thought I'd try it. :)
The attempt was as follows...
w = 2(pi)f = sqrt(g/L)

I then squared both sides to get (2(pi)f)^2 = g/L

Then simplified to L = g/(2(pi)f)^2) --Hence epic fail, for, come to find out, sqrt(g/l) is for pendulums. --

And now I'm lost. -.-
 

Answers and Replies

Kurdt
Staff Emeritus
Science Advisor
Gold Member
4,769
6
Its really rather more simple than that. A tube closed at one end will have a fundamental frequency, where the wavelength is 4 times the tubes length.
 

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