Calculating Temperature Rise in 100m Waterfall: Heat Energy Questions

AI Thread Summary
To calculate the temperature rise in a 100m waterfall, the potential energy (P.E.) of the falling water is converted into heat energy. The equation P.E. = mgh can be used, where g is the acceleration due to gravity (9.8 m/s²) and h is the height (100m). Setting the potential energy equal to the heat energy (Q), the equation becomes M(9.8)(100) = mcΔT. The challenge lies in determining the mass (m) and specific heat capacity (c) of the water, which are necessary to solve for the temperature change (ΔT). Understanding these relationships is crucial for completing the calculation.
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Homework Statement


Much of the energy of falling water in a waterfall is converted into heat.

If all the mechanical energy is converted into heat that stays in the water, how much of a rise in temperature occurs in a 100 m waterfall?


Homework Equations


q=mc(Tf-Ti)
Q=mc Delta T
Delta T = |Tf-Ti|


The Attempt at a Solution



i have no idea where to start or what equation to use all i see is the 100m can some one please lead me in the correct direction with the correct formula to use.
 
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potential energy = mgh

This is the energy available to be converted to heat.
 
ok so P.E.=MGH

P.E. = M(9.8)(100)

is this correct there are still 2 unknows
 
If all the energy is converted into heat then P.E. = Q

Set them equal and solve for delta T.
 
ok so the equation would look like this

M(9.8)(100) = mc Delta T

but i still need to know the Mass and MC am i overlooking something??
 
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