Calculating the Coefficient of Static Friction

AI Thread Summary
To find the coefficient of static friction for a 25 kg chair requiring 365 N to start moving, divide the force by the weight of the chair (approximately 245 N), resulting in a static friction coefficient of about 1.49. For kinetic friction, with a constant velocity maintained by 327 N, divide this force by the same weight, yielding a kinetic friction coefficient of approximately 1.33. The discussion highlights the importance of using textbook formulas for solving physics problems. The original poster initially struggled but later found the answers independently. Understanding these coefficients is crucial for analyzing motion and friction in physics.
Sachin_Sharma
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Homework Statement



A 25 kg chair intially at rest on a horizontal floor requires 365 N horizontal force to set it in motion. Once the chair is in motion, a 327 N horizontal force keeps it moving at a constant velocity.

A: Find the coefficient of Static Friction between the chair and the floor
B: Find the coefficient of Kinetic Friction between the chair and the florr.

Homework Equations



I am very new to physics and my teacher has been absent for the entire week. I have no idea where to begin and what equations to use. I really hope that someone out there can help me in my plight.

The Attempt at a Solution

 
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Hi Sachin_Sharma, welcome to PF.
You must have a textbook. Now what is the expression for the frictional force?
 
Thanks so much! I really should have taken this posting down because I actually did manage to find the answer by using my textbook! I was one step ahead of you, but I nonetheless appreciate your posting rl.bhat.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

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