Calculating the Radius of a Geosynchronous Satellite Orbit Around Earth

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Homework Help Overview

The discussion centers around calculating the radius of a geosynchronous satellite orbiting Earth. The problem involves understanding the characteristics of geosynchronous satellites and the relevant physical principles governing orbital motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to start the problem. Some participants discuss the orbital period of geosynchronous satellites and mention relevant equations, while others highlight the need to incorporate gravitational forces into the calculations.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some guidance has been offered regarding the importance of gravitational considerations, but there is no explicit consensus on the approach to take.

Contextual Notes

The original poster has provided specific constants for the problem, and there is an emphasis on understanding the definitions and characteristics of geosynchronous satellites.

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Homework Statement


http://i241.photobucket.com/albums/ff4/alg5045/MUG_co_6.jpg

A satellite that goes around the Earth once every 24 hours is called a geosynchronous satellite is in an equatorial orbit, its position appears stationary with respect to a ground station, and it is known as a geostationary satellite.

Find the radius R of the orbit of a geosynchronous satellite that circles the earth. (Note that R is measured from the center of the earth, not the surface) You may use the following constants:

G=6.67*10^-11
mass of the Earth = 5.98*10^24 kg
radius of the Earth = 6.38*10^6 m


Homework Equations





The Attempt at a Solution



I have no idea how to even begin this problem.
 
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What is a geosynchronous satellite's orbital period? What are the relevant equations regarding orbital period?
 
The orbital period is 24 hours or 86400 seconds. I think the relevant equation is v = 2(pi)(r)/T.
 
You aren't incorporating gravity. You need to do that.
 

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