Calculating Thermodynamic Values for Different Processes

AI Thread Summary
To calculate thermodynamic values for the process from A to B in figure 2, the specific type of process is not necessary. The work can be determined by integrating or calculating the area under the AB line, which consists of a right triangle and a rectangle. The triangle's area is calculated as 1000 J, while the rectangle's area is 400 J, leading to a total work of 1400 J. Once the work is established, the other thermodynamic values such as q, ∆U, ∆H, and ∆S can be derived. This method simplifies the calculation process for the given thermodynamic scenario.
atsum
Messages
9
Reaction score
0
The question is to calculate: q, w, ∆U, ∆H, ∆S for each step(A to B, B to C, C to A)

I know how to calculate the values on figure 1, but, how to calculate A to B on figure 2?

For A to B on figure 1, it is isothermal process, therefore, I can easy to find out the answer, but I don't know what is the process for A to B on figure 2.

Can anyone tell me what the condition difference (A to B) between figure 1 and 2?
 

Attachments

  • 擷取.JPG
    擷取.JPG
    13.8 KB · Views: 494
Science news on Phys.org
atsum said:
For A to B on figure 1, it is isothermal process, therefore, I can easy to find out the answer, but I don't know what is the process for A to B on figure 2.

Can anyone tell me what the condition difference (A to B) between figure 1 and 2?

Hello.

You don't need to know what kind of process is between A and B on picture 2. You simply calculate work by integrating, or simpler, by calculating surface under the AB line. It is easy to calculate, because you have one right angled triangle and one rectangle. (i will do approximation: 1atm=10^5 Pa, a 1L=1dm^3=10^-3 m^3)

Surface of triangle is:

S(t)=\frac{pV}{2}=\frac{5*10^{5}Pa*4*10^{-3}m^{3}}{2}=1000J

Surface of rectangle is:

S(r)=pV=10^{5}Pa*4*10^{-3}m=400J

So, total work is W=S(t)+S(r)=1400J

And now you can calculate everything else.
 
P.S. I have some technical issues here.. you can copy these formula code into this application, and you will see it: http://www.codecogs.com/latex/eqneditor.php
 
I was watching a Khan Academy video on entropy called: Reconciling thermodynamic and state definitions of entropy. So in the video it says: Let's say I have a container. And in that container, I have gas particles and they're bouncing around like gas particles tend to do, creating some pressure on the container of a certain volume. And let's say I have n particles. Now, each of these particles could be in x different states. Now, if each of them can be in x different states, how many total...
Thread 'Why work is PdV and not (P+dP)dV in an isothermal process?'
Let's say we have a cylinder of volume V1 with a frictionless movable piston and some gas trapped inside with pressure P1 and temperature T1. On top of the piston lay some small pebbles that add weight and essentially create the pressure P1. Also the system is inside a reservoir of water that keeps its temperature constant at T1. The system is in equilibrium at V1, P1, T1. Now let's say i put another very small pebble on top of the piston (0,00001kg) and after some seconds the system...
Back
Top