The discussion centers on calculating the thrust acting on the curved surface of a cylindrical vessel filled with water to a height of 10 m. It is established that the thrust on the curved surface equals the thrust at the bottom of the vessel. Using the equation P=F/A and the volume formula Vol = πr²h, participants explore the implications of atmospheric pressure supporting a 10 m water column to determine the vessel's radius, leading to options of 5 m, 10 m, 15 m, or 25 m.
PREREQUISITESStudents in engineering or physics, particularly those focusing on fluid mechanics, as well as professionals involved in designing cylindrical storage vessels or similar structures.
This may be a key to help you find their relation. Can you get any idea from this information?Pyrus said:It is found that the thrust acting on the curved surface is equal to that at the bottom.
Since you have posted no attempt, I assume you are stuck on interpreting the question.Pyrus said:Homework Statement
A large cylindrical vessel contains water to a height of 10 m. It is found that the thrust acting on the curved surface is equal to that at the bottom. If atmospheric pressure can support a water column of 10 m, the radius of the vessel is:-
(a) 10 m (b) 15m (c) 5 m (d) 25 m
Homework Equations
P=F/A
Vol = πr*r*h
The Attempt at a Solution
In understanding what they mean or in calculating it?Pyrus said:I stuck up in force acting on curved surface of cylinder.