Calculating Time for Rectangular Block to Stop on Rough Ground

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To calculate the time taken for a rectangular block to stop on rough ground, the deceleration depends on whether the entire block is on the rough surface or only part of it. When the entire block is on the rough ground, the maximum deceleration is given by a = (mu)g. The problem can be approached by considering two cases: when the length of the block on the rough ground is less than or equal to L, and when it exceeds L. The relationship between initial velocity, distance, and time can be derived using kinematic equations. Ultimately, the time can be determined by solving the equations while ensuring the discriminant equals zero.
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Homework Statement


A rectangular block of length L is traveling on a smooth surface at velocity u. When it encounters rough ground with coefficient of friction mu, it decelerates to a stop. What is the time taken for the rectangular block to stop?

Homework Equations


F= (mu)mg

The Attempt at a Solution


Deceleration of the block is given by a = (mu)gx/L if only part of the block is on the rough ground. If the entire block is on the rough ground, the maximum deceleration is given by a = (mu)g. This means i have to split the question into two cases.
1. time taken when x is less than or equal to L
2. time taken when x is greater than L

But I am stuck here. I don't know how to relate x to t and u.
 
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Friction force is independent of area of contact. So I think there is no need for taking a part of the block.

deceleration of the block is (mu)g
apply kinematics equation
v^2 - u^2 =2as
v=0 s=L
find a relation between u and s from here
use another equation - s=ut +0.5at^2
find out time from this equation. ( here discriminant will become 0 from previous equation.)
 
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