- #1

siva surya

- 7

- 0

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

In summary: Maybe try drawing a picture, and labeling the forces and distances, and email that picture.In summary, the conversation revolves around calculating the torque required to rotate an axle and wheel system with a hanging weight of 10 kg. The torque is dependent on the acceleration and moment of inertia of the system. The mass of the axle and wheel can be determined by considering the forces applied and ensuring that the system is strong enough to withstand these forces. There is also a discussion about using gravity as a source of energy and estimating the impact force of a falling mass. Finally, the conversation shifts to determining the torque required to pull up a weight of 11 kg from a distance of 100 cm through a wheel and axle system. The estimated torque for

- #1

siva surya

- 7

- 0

Physics news on Phys.org

- #2

billy_joule

Science Advisor

- 1,200

- 331

It may be that:

T = Fr where the force is due to the 10kg mass and r is the radius of the axle?

- #3

- #4

billy_joule

Science Advisor

- 1,200

- 331

siva surya said:in this

1.how much torque is reuired to rotate axle of diameter 10 cm

2.and on the other end wheel is attached of diameter 100 cm and hang with 10 kg of weight

3.then in how many kg should be axle and wheel metal ?

1. It depends on how fast you want the system to accelerate.

T = Iα

Where T is torque, I is moment of inertia and α is angular acceleration.

The moment of inertia depends on geometry and mass:

https://en.wikipedia.org/wiki/Moment_of_inertia

The above only considers the torque required to accelerate the axle & pulley, additional torque will be required to accelerate the hanging mass upwards.

3. The mass of the axle & wheel will be the volume multiplied by density. The required geometry will depend on the forces applied, in other words it needs to be of a certain size (and mass) so it doesn't break.

Is this homework? Or a real project? Maybe you are trying to design a hand winch?

https://www.google.co.nz/search?q=h...Cc#q=hand+winch&tbm=isch&tbs=isz:lt,islt:svga

- #5

siva surya

- 7

- 0

i like to design no energy machine

- #6

billy_joule

Science Advisor

- 1,200

- 331

A machine, by definition, uses energy.

https://en.wikipedia.org/wiki/Machine

https://en.wikipedia.org/wiki/Machine

- #7

siva surya

- 7

- 0

ya like to use gravity as energy

- #8

CWatters

Science Advisor

Homework Helper

Gold Member

- 10,544

- 2,323

siva surya said:1.how much torque is reuired to rotate axle of diameter 10 cm

2.and on the other end wheel is attached of diameter 100 cm and hang with 10 kg of weight

The torque must be at least..

= (10Kg * 9.81) * 100/10

= 981 Nm

That torque will stop the weight falling. If you want to raise the weight then (as billy said) you need to tell us how fast you want it to accelerate and the moment of inertia of the pulleys etc. Friction?

- #9

siva surya

- 7

- 0

if the 10 kg mass falls as free fall and create impact force means what's the impact force on there

in which mass 10 kg

height 20 cm

whats Newton there

in which mass 10 kg

height 20 cm

whats Newton there

Last edited by a moderator:

- #10

CWatters

Science Advisor

Homework Helper

Gold Member

- 10,544

- 2,323

If you assume it hits something like modelling clay and has constant deceleration you can estimate using..

V

where

U

V

a = acceleration

s = distance (eg depth of impact crater)

So you could measure the depth of the impact crater and plug in the numbers to estimate the deceleration "a".

Then use F = ma to estimate the implied impact force.

The results will be very approximate. In the real world it's better to attach an accelerometer to the mass and measure "a".

- #11

siva surya

- 7

- 0

how much torque is required to pull up to weight 11 kg from 100 cm through wheel and axle?

- #12

siva surya

- 7

- 0

how much torque is required to pull up to weight 11 kg from 100 cm through wheel and axle?CWatters said:

If you assume it hits something like modelling clay and has constant deceleration you can estimate using..

V^{2}= U^{2}+2as

where

U^{2}= velocity at impact

V^{2}= velocity after impact, probably zero

a = acceleration

s = distance (eg depth of impact crater)

So you could measure the depth of the impact crater and plug in the numbers to estimate the deceleration "a".

Then use F = ma to estimate the implied impact force.

The results will be very approximate. In the real world it's better to attach an accelerometer to the mass and measure "a".

- #13

TESL@

- 122

- 8

110 Nm

- #14

CWatters

Science Advisor

Homework Helper

Gold Member

- 10,544

- 2,323

siva surya said:how much torque is required to pull up to weight 11 kg from 100 cm through wheel and axle?

In post #8 I showed you how to calculate the torque for 10kg...

CWatters said:The torque must be at least..

= (10Kg * 9.81) * 100/10

= 981 Nm

For 11kg the sum becomes..

= (11Kg * 9.81) * 100/10

= 1079 Nm

or has your system changed?

- #15

CWatters

Science Advisor

Homework Helper

Gold Member

- 10,544

- 2,323

PS: It's hard to understand your English.

To calculate torque, you will need to know the radius of the axle and the wheel, as well as the force applied to the wheel. The formula for torque is torque = force x radius. In this case, you will need to convert the radius of the axle to meters, as the formula requires units of meters. So, if the radius of the axle is 10 cm, it would be converted to 0.1 meters. Then, you can plug in the values and solve for torque.

Torque is typically measured in units of Newton-meters (N*m) in the metric system or foot-pounds (ft-lb) in the imperial system.

The length of the axle and wheel can affect the amount of torque required to turn the wheel. The longer the axle and wheel, the more torque is needed to overcome the resistance and rotate the wheel. This is because the longer the distance from the center of rotation, the greater the lever arm and the more torque is needed to produce the same amount of rotation.

Yes, torque can be negative. Negative torque, also known as "reverse torque," occurs when the direction of rotation is opposite to the direction of the applied force. This can happen in situations where the force is trying to slow down or stop the rotation of the wheel.

Torque and power are related, but they are not the same. Torque is the measure of rotational force, while power is the rate at which work is done. The relationship between torque and power is described by the equation power = torque x angular velocity. This means that a higher torque can result in a higher power output, but it also depends on the speed at which the torque is being applied.

- Replies
- 5

- Views
- 960

- Replies
- 4

- Views
- 2K

- Replies
- 9

- Views
- 1K

- Replies
- 16

- Views
- 2K

- Replies
- 10

- Views
- 5K

- Replies
- 4

- Views
- 1K

- Replies
- 2

- Views
- 977

- Replies
- 9

- Views
- 861

- Replies
- 21

- Views
- 3K

- Replies
- 4

- Views
- 2K

Share: