Calculating Torque for a Robot Wheel: Mass, Acceleration, and Constant Velocity

  • Thread starter Thread starter elimenohpee
  • Start date Start date
  • Tags Tags
    Torque Wheel
Click For Summary
SUMMARY

The discussion focuses on calculating the torque required for a robot wheel with a mass of 3 kg and a diameter of 0.0381 m. The initial torque calculation using the formula torque = mass * gravity * radius resulted in 1.12 Nm. However, participants clarified that torque should be calculated using the cross product of radius and force, emphasizing that radius refers to the distance from the axis of rotation, not the diameter. The correct approach for calculating torque during acceleration and at constant velocity was also addressed.

PREREQUISITES
  • Understanding of basic physics concepts, specifically torque and force.
  • Familiarity with the formula for torque: τ = r × F.
  • Knowledge of linear acceleration and its relationship with torque.
  • Basic understanding of rotational dynamics and the role of radius in torque calculations.
NEXT STEPS
  • Research the application of torque in robotics, specifically for motor design.
  • Learn about the differences between linear and angular acceleration.
  • Study the effects of friction and load on torque calculations in mechanical systems.
  • Explore advanced torque calculation techniques using vector analysis.
USEFUL FOR

Engineers, robotics enthusiasts, and students studying mechanical engineering who are involved in designing motor systems and calculating torque for robotic applications.

elimenohpee
Messages
64
Reaction score
0

Homework Statement


You are given a robot, and you are asked to design the torque needed for the driving motor. What is the torque to turn a wheel who's mass of the system connected to the rim is 3kg, and the diameter of the rim is 0.0381m?

What is the torque when the wheel accelerates at a rate of 1.47m/s^2? What is the torque when the wheel reaches a constant velocity of 5 m/s?


The Attempt at a Solution



I know torque = force * distance = mass * acceleration * distance

I figured the torque to turn the wheel would be:
torque = m*g*r = 3*9.81*0.0381 = 1.12Nm (but this sounds like a lot for such a small mass)

but I'm not sure what to do when the wheel is to accelerate. And I'm lost what to do when the acceleration is zero, aka constant velocity.
 
Physics news on Phys.org
elimenohpee said:
I know torque = force * distance = mass * acceleration * distance

I figured the torque to turn the wheel would be:
torque = m*g*r = 3*9.81*0.0381 = 1.12Nm (but this sounds like a lot for such a small mass)

but I'm not sure what to do when the wheel is to accelerate. And I'm lost what to do when the acceleration is zero, aka constant velocity.

sorry but...your torque equation is wrong
remember that torque is r X F not r * F
r X F is also rFsin(theta), with theta as the angle between them
also that r is not the diameter of the wheel
it's the distance from the point of force applied
since it is a wheel, u can tpretty much use the center for axis of rotation and the distance to where it spins is yyour r
 
Yes I'm aware that, the angle between the vectors was assumed to be pi/2. And that distance given was the radius of the wheel, since the force is assumed to applied at the center of the rim.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
19
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
4
Views
2K
Replies
9
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
16
Views
2K
Replies
33
Views
12K