Calculating Velocity and Direction at Height of 120m

AI Thread Summary
A particle is projected at a velocity of 146 m/s and an elevation of 35 degrees, reaching a maximum height of 357.8 m and a horizontal distance of 2041.8 m. The discussion focuses on calculating the velocity and direction of the particle at a height of 120 m, with a calculated velocity of 137.72 m/s. The correct direction of motion at that height is determined to be 29.72 degrees from the horizontal. This angle indicates the trajectory of the particle as it ascends or descends at that specific height. Understanding these calculations is crucial for analyzing projectile motion effectively.
stupif
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A particle is projected with a velocity of 146m/s at an elevation of 35degree.
max height= 357.8, t=17.1s horizontal distance= 2041.8m

the question is find the velocity and direction of motion at a height of 120m
i got v= 137.72, but what is the meaning of the direction of motion at a height of 120m, the correct answer is 29.72degree

thank you
 
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It means at what angle the particle is moving. 29.72 degrees presumably means 29.72 degrees from the horizontal.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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