Calculating Velocity in the Y-Direction: Seeking Help

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The discussion focuses on calculating the velocity in the y-direction for a physics problem involving a water drop. Participants note the lack of axis labels in the provided image, questioning the definitions of the x and y axes. The time taken for the water drop to fall 1 meter is identified as the same time it takes to travel 10 meters horizontally, allowing for the calculation of horizontal velocity. The relationship between horizontal distance, time, and constant velocity in the x-direction is emphasized as a key aspect of the solution. Understanding the role of gravity in the y-direction is also highlighted as essential for solving the problem.
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I do not see how to calculate the velocity in the y-direction...any help is appreciated...all information is given

Problem is found here...

Thanks for the help


http://img214.imageshack.us/img214/5904/physicsxn6.png
 
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I do not see how to calculate the velocity in the y-direction...any help is appreciated...all information is given

Problem is found here...

Thanks for the help


http://img214.imageshack.us/img214/5904/physicsxn6.png
 
Last edited by a moderator:
I do not see any axis lables. What is y? what is x?
 
You probably meant the velocity in the x-direction.

You calculated the time it takes a water drop exiting the soaker to drop throught a height of 1 meter. This is also the time it takes the same water drop to travel a horizontal distance of 10 meters (during the same time). So its horizontal speed is

v_x = \frac{horizontal\ distance\ travelled}{time\ to\ travel\ this\ distance}
 
y is the direction of gravity.

Just use the distance and the fact that the velocity in the x-direction remains constant to calculate the velocity given you know the time.
 
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