Calculating Voltage at Terminal A in a Two-Terminal Circuit

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To calculate the voltage at terminal A with respect to terminal B in a two-terminal circuit, the voltage across the 3 Ohm resistor is determined to be 6 V. The 1 Ohm resistor can be ignored as it does not affect the current flow. The total resistance in the series circuit is 5 Ohms, leading to a current of 2 A. The voltage across the 3 Ohm resistor is confirmed using the formula V = IR, resulting in 6 V. Alternative verification methods, such as the voltage divider equation and KCL analysis, also yield the same result.
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Homework Statement



help please! i am trying to find V at terminal A with respect to B

Homework Equations


V=IR
I=V/R

The Attempt at a Solution


so this is my thought process:
the answer should be 10 V because the voltage is the same for a parallel resistor, but the thing that throws me off is that terminal is has a resistance of 1 Ohm so I'm not sure if my answer is right. help please and thank you.
 
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That's incorrect. The 1 Ohm resistor is just a wire as there is no current flowing through it so it can be ignored. So now you basically just have that first loop. The voltage across terminals A and B is the same as the voltage across the 3 Ohm resistor, right? How can you find the voltage across that resistor?
 
okay. with that info, i got the voltage across the 3Ohm resistor to be 6.00 A

is this right?

because i added 2 and 3 since it is in series so that gives total resistance
v=IR
I=V/R
I=10/5
I=2
V=IR for the 3Ohm resistor
V=2(3) = 6
 
Yep that's right. Also, if you want to verify your answer you could do a Voltage divider equation... V = 10V * (3 / (3+2) ) = 6 or KCL analysis at that top node so (V1 - 10V)/2 + (V1 - 0)/3 = 0 and then solve for V1 which ends up being 6V.

Of course the way you did it is the easier way, I'm just showing you other approaches and verifying your answer :p
 
thanks for the help. and i meant 6.00 V, not 6.00 A but I'm sure you figured that out
 
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