Calculating Wavelength in Young's Interference Experiment

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In a Young's interference experiment using monochromatic light, the user is tasked with calculating the wavelength based on given parameters: slit separation (d = 0.50 mm), distance to the screen (L = 3.3 m), and the position of the first maximum (y1 = 3.4 mm). The relevant equation used is Yn = (nλL)/d, where n represents the order of the maximum. The user correctly identifies that for the first maximum, n should equal 1, leading to the equation 3.4 mm = (1 * λ * 3.3 m) / 0.50 mm. After calculations, the user arrives at a wavelength of approximately 0.5151 mm and seeks confirmation on their approach, particularly regarding the interpretation of n. The discussion emphasizes the importance of correctly identifying the order of the maximum in the calculations.
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So I got a warning for just posting questions so I'll do as best as I can to try and put effort lol

Homework Statement



A Young's interference experiment is performed with monochromatic light. The separation between the slits, d, is .50 mm, and the interference
pattern on a screen L = 3.3 m away shows the first maximum y1 = 3.4 mm from the center of the pattern. What is the wavelength?


GIVEN DATA

d=.50mm

L=3.3m

y1= 3.4mm


Homework Equations



Yn=(nλL)/d

The Attempt at a Solution



I need to know if I'm attempting this right.

I started off by plugging in y1=3.4mm, L=3.3m and d=.50mm

Pretty simple.
3.4=(nλ3.3)/.5

1.7=(nλ3.3)

.5151...=λ

?

Am I right by plugging in 1 for n?
 
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Quoting from the text you provided "first maximum y1 = 3.4 mm".
 
So... Am I right?
 
elementozzy said:
So... Am I right?

Do you need to ask? the formula given is for yn, you were given y1, what do you think n is?
 
Oh I just needed to make sure. So yn(subscript), whatever is in the subscript is just n?
 

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