B Calculating Wind Turbine Torque - Get the Right Result!

AI Thread Summary
The discussion focuses on discrepancies in calculating wind turbine torque, with participants noting that their results do not match the expected values. There is a consensus that the author of the referenced book may have omitted a power of ten in the calculations. Participants also express confusion regarding the use of symbols for moment of inertia, with one noting the distinction between moment of inertia and polar moment. Calculated values for torque and moment of inertia are shared, indicating a significant difference from the author's figures. Overall, the conversation highlights the need for clarity in formulas and dimensions in wind turbine calculations.
neonwarrior
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Hello everyone,

I am reading a book about wind power turbines and found a calculation. I tried it myself and the numbers doesn't match.

Here is an image of the data and result.
Capture.PNG


I don't get to the same torque.

And also what do you think about the moment of inertia value?

Before the data the author gave the formula:

1665195381364.png


Thanks in advance
 
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Hi,

neonwarrior said:
I don't get to the same torque.
I don't get the same torque either. Do we agree on some value ?
[edit] It might just be a simple power of 10 the author 'forgot')

And also what do you think about the moment of inertia value?
Again, what do you get for a reasonable size windmill ?

[edit] The author makes a mess of symbols and dimensions. Uses ##J## for moment of inertia (the 7500 kg/m2) AND for polar moment (m4) .
I find no way to balance dimensions in ##(5-4)##

##\ ##
 
Last edited:
Hi BvU,
Thank you for your reply.

I wasn't aware that there was another moment of inertia (the polar). It's time to read myselft a physics textbook first LOL.

What I get is :

In the first one: converting first the rpm to rad/s

Net torque = J . (DELTA w)/ 5 seconds = 785.4 Nm

And the other question:
I calculated from some papers of windmills a moment of inertia of 113,000 kgm2

from a paper.PNG


And from this paper there are some values: https://core.ac.uk/download/pdf/70596755.pdf
values.PNG


Yes, as you said, I think also there is a 10 factor missing or something.

Neonwarrior
 
neonwarrior said:
Net torque = J . (DELTA w)/ 5 seconds = 785.4 Nm
Same here -- from the given data.

##I## is the symbol of choice for moment of inertia. With three blades times ##{1\over 3} ML^2##, 50 m long wings you would have left over 1 kg of mass for each wing :oldlaugh: if the total ##I## is 7500 kg m2

These guys mention 12.5 tonne per blade... so more like a factor of 10000 ...

##\ ##
 
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This has been discussed many times on PF, and will likely come up again, so the video might come handy. Previous threads: https://www.physicsforums.com/threads/is-a-treadmill-incline-just-a-marketing-gimmick.937725/ https://www.physicsforums.com/threads/work-done-running-on-an-inclined-treadmill.927825/ https://www.physicsforums.com/threads/how-do-we-calculate-the-energy-we-used-to-do-something.1052162/
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