Calculation of g force on an bank of an aeroplane

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To calculate the G force on an airplane turning uniformly, the formula f=mv^2/r is used, where mass is 79,015 kg, velocity is 257.2 m/s, and radius is 100 meters, resulting in a force of approximately 52,269,876.376 N. This force leads to an acceleration of 661.51 m/s², which translates to a G force of 67.5 Gs when divided by 9.8 m/s². However, this calculation only considers the horizontal component of the loading factor, and the vertical G force due to gravity must also be factored in for a complete analysis. Ultimately, such a tight turn at high speed would exceed the structural limits of the aircraft, making it impossible for the plane to perform safely. This illustrates why airplanes cannot execute such maneuvers at high velocities.
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can anyone tell me how to calculate G force of an airplane of mass=79015, velocity=257.2 m/s turning uniformly at a radius of 100 meters.
I use the formula as f=mv^2/r
i don't know if its correct but i get an answer of f=52269876.376
then i substituted in the equation f=ma .. and i got a= 661.51 m/sec^2
finally i used G=a/g. i got G= 661.51/9.8
and i got 67.5 g's... please help me with this problem .
 
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And now you know why airplanes do not make such turns when traveling at such high speeds.

Technically, you've only computed the horizontal component of the loading factor. If you had a smaller load, you'd have to combine it with vertical 1g due to gravity. But in this case, it won't make any difference.
 
It's simple: a plane traveling at 257.2 m/s can't turn this tightly without coming apart. Anyone aboard has already blacked out.
 

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