Calculus: Coordinate Changes, Jacobian, Double Integrals?

PinkPocky
Messages
2
Reaction score
0
Calculus: Coordinate Changes, Jacobian, Double Integrals??

Homework Statement



Show that T(u,v) = (u2 - v2, 2uv)
maps to the triangle = { (u,v) | 0 ≤ v ≤ u ≤ 3 } to the domain D,
bounded by x=0, y=0, and y2 = 324 - 36x.

Use T to calculate ∬sqrt(x2+y2) dxdy on the region D.


Homework Equations



The Attempt at a Solution



I know that dxdy = the Jacobian = (4u2+4v2)dudv.

I'm have a really hard time finding a way to figure what the bounds of the integral are, in terms of u and v.
 
Physics news on Phys.org


PinkPocky said:

Homework Statement



Show that T(u,v) = (u2 - v2, 2uv)
maps to the triangle = { (u,v) | 0 ≤ v ≤ u ≤ 3 } to the domain D,
bounded by x=0, y=0, and y2 = 324 - 36x.

Use T to calculate ∬sqrt(x2+y2) dxdy on the region D.


Homework Equations



The Attempt at a Solution



I know that dxdy = the Jacobian = (4u2+4v2)dudv.

I'm have a really hard time finding a way to figure what the bounds of the integral are, in terms of u and v.

Try drawing a picture of the uv region. You have 0 ≤ v ≤ u ≤ 3 given. Both u and v are between 0 and 3 so draw that square for a start. Now shade what part of that square also has v ≤ u. Then put your uv limits as that picture requires, like any other area problem.
 


Great, thanks! I should have realized it before... but thank you, a really great explanation made it clear for me to help myself. :)

By the way, the final answer to the problem I solved for was ridiculous but correct. The solved integral is equal to 4536/5, or 907.2 :(... haha.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top