Jonmundsson
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Homework Statement
Let
\begin{equation*}<br /> f(x,y) = \begin{cases} \dfrac{x^3 - y^3}{x^2 + y^2}, \hspace{1.1em} (x, y) \neq (0,0) \\ 0, \hspace{4em} (x,y) = (0,0) \end{cases}<br /> \end{equation*}
Is f continuous at the point (0,0)? Are f_x og f_y continuous at the point (0,0)?
Homework Equations
Polar coords
The Attempt at a Solution
If you convert f to polar it's easy to see that it is continuous (since it doesn't depend on \theta. I'm just wondering if the derivative of the polar function is dependent on \theta then it isn't continuous and therefore neither are f_x and f_y
Steps:
\displaystyle \lim _{(x,y) \to (0,0)} \dfrac{x^3 - y^3}{x^2 + y^2} = \lim _{r \to 0} \hspace{0.3em} r (cos^3 \theta - sin^3 \theta) = 0
Define g(r) = r (cos^3 \theta - sin^3 \theta) then g'(r) = cos^3 \theta - sin^3 \theta and \displaystyle \lim _{r \to 0} cos^3 \theta - sin^3 \theta doesn't exist.
Cheers.