Calculus-integration over mass

  • Context: Undergrad 
  • Thread starter Thread starter chandran
  • Start date Start date
  • Tags Tags
    Mass
Click For Summary

Discussion Overview

The discussion revolves around the concept of integration in calculus, specifically focusing on integrals over mass, area, and line. Participants express confusion regarding the application of these integrals in contexts such as calculating the moment of inertia and visualizing different types of integrals.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant expresses confusion about integrating over mass, area, and line, particularly in the context of moment of inertia and how these integrals relate to familiar concepts in calculus.
  • Another participant explains that for an infinitesimal mass, the relationship dm = ρ dV is used, where ρ is the mass density, leading to the integral M = ∫ dm = ∫ ρ dV for the total mass.
  • The explanation continues with the idea that if density is uniform, the mass can be simplified to M = ρV, which is a familiar result.
  • Participants discuss the application of line and surface integrals in electrostatics, introducing concepts like line charge (dλ = Q dl) and surface charge (dσ = Q dA), noting the similarity to the mass integral.
  • One participant references an existing thread in the math section for further exploration of the topic.
  • Another participant mentions a previous question they asked on a similar topic, suggesting that insightful answers were provided in that discussion.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the visualization of integration over line and area, and the discussion remains open with various perspectives and references to related threads.

Contextual Notes

Participants express uncertainty about the visualization of integrals over different dimensions and the application of these concepts in physical contexts. There are references to previous discussions that may provide additional insights but do not resolve the current questions.

chandran
Messages
137
Reaction score
1
There are certain integrals which say integration over all m ,integration over all area,integration over line. I am confused with this. In calulus i am comfortable with integration with limits of an independent variable and the
integration results in the area under the curve. But in doing the moment of inertia of a solid about the axis a small dm is present inside the integral
and we say to integrate it for M. What is this integration about M exactly .

Similarly what is integration over line and area. How can i visualize this?
 
Physics news on Phys.org
chandran said:
There are certain integrals which say integration over all m ,integration over all area,integration over line. I am confused with this. In calulus i am comfortable with integration with limits of an independent variable and the
integration results in the area under the curve. But in doing the moment of inertia of a solid about the axis a small dm is present inside the integral
and we say to integrate it for M. What is this integration about M exactly .

Similarly what is integration over line and area. How can i visualize this?

For an infinitesimal mass, what you have is

[itex]dm = \rho dV[/itex]

where [itex]\rho[/itex] is the mass density. So, in general, the mass of the object is the integral of dm over the volume that is occupied by that object, i.e.

[itex]M = \int dm = \int \rho dV[/itex]

If the density is uniform throughout the mass, then you can factor the density out of the integral and all you have, after doing the integral is

[itex]M = \rho V[/itex]

which is what you are familiar with as the mass of the object.

The line and surface integral usually comes in in electrostatic. What you are doing actually is doing a line charge and surface charge integral. So instead of dm, you have [itex]d\lambda[/itex] or [itex]d\sigma[/itex] where [itex]\lambda[/itex] is the infinitesimal line charge defined as

[itex]\lambda = Q dl[/itex]

and [itex]d\sigma[/itex] is defined as

[itex]d\sigma = Q dA[/itex].

You'll notice that this is of similar form that we had for dm, where the "nature" of the quantity (i.e. mass M, or charge Q) is paired with the "dimension", i.e volume or length or area.

Zz.
 
Last edited:

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
1K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
5
Views
2K