Calculus Limits: Verifying the Solution for (x+∆x)^2 - x^2 / x

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The discussion focuses on verifying the limit of the expression ( (x+∆x)^2 - x^2 ) / x as ∆x approaches 0. The initial calculation led to an incorrect result of 2x + a, but after expanding and simplifying, the correct limit was found to be 2x. Participants clarified that dividing by ∆x instead of x was necessary for the correct approach. The final confirmation highlighted that 2x is also the derivative of x². This reinforces the connection between limits and derivatives in calculus.
kendal12
I just started calculus and we are doing limits. I was doing fine until I ran across this problem:

lim ( (x+∆x)^2 - x^2 ) / x
∆x approaches 0

I substituted delta x for a and ended up with 2x + a

I don't think this is right for some reason, but I think I did everything right, can someone please verify my answer so that I know I am on the right track? thanks!
 
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Just expand it out. (note that a = \Delta x) (x+a )^{2} - x^{2} = 2ax + a^{2}. So we have \frac{2ax + a^{2}}{x}. Divide through by x. What do you notice when you substitute a = 0.
 
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I actually messed up when I typed that problem. It should all be over delta x. I'm so sorry! So I divided through by a and got a + 2x. Then substituted o in for a, so I'm left with 2x. Right?
 
2x, you are right !
Remember this calculation, since you will learn soon that 2x is the derivative of x².
 
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