Can a Function Have a Horizontal Asymptote and Intersect It Infinitely?

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Homework Statement



2 problems.

1)
Find an example of a function f such that :
the line y=2 is a horizontal asymptote of the curve y=f(x)
the curve intersects the line y=2 at the infinitive number of points

2)
The position of an object moving along x-axis is given at time t by:
s(t)= 4t-4 if 2<t<8
and = -68 +t(20-t) if 8<=t<=10

Determine the acceleration and the velocity at any time t. Is the velocity continuous? Is acceleration continuous?

Homework Equations


The Attempt at a Solution

For the first one, I'm really puzzled how y=2 can be horizontal asymptote, AND that the curve intersects it at infinitive points.

I'm guessing that the function is y=2cos(1/x), as , y=2 is an asymptote even if my guess is right, how exactly should I solve that?

For the second one, I found derivatives of s and s'

s'= 4 if 2<t<8
s'= 20-2t if 8<=t<=10
s''=0 if 2<t<8 and
s"= -2 if 8<=t<=10

what then? how do i check if they are continuous?

I know the definition of continuous function and what exactly is horizontal asymptote, but I have no idea how to solve these two problems here :(.

Help!
 
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1. I guess your example is correct. You should use whatever definition of asymptote you have and see if it applies to your example. Just another, maybe slightly simpler example: 2+sin(x)/x

2. Just check if the functions "fit together" at t=8. For the velocity, you have 4 and 20-2*8=4, so the velocity is continuous. For the acceleration, you have 0 and -2, so the acceleration is non-continuous. In this case, continuity just means that you can draw the graph of the function without having to lift the pen at some point, so it's very intuitive. Check http://en.wikipedia.org/wiki/Piecewise
 
1. Yeah I figured my example was correct, does my function pass the fact that

"the curve intersects the line y=2 at the infinitive number of points" though?

I just have no idea if it does or not.

2. I kinda figured that actually later onThank you for your answer!
 
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Sorry for bumping, I still am not really sure if I did #1 right, both
y=2cos(1/x) and y=2+sinx/x do seem to have y=2 as horizontal asymptotes, but I am not really sure how the curves intersects the line y=2 at the infinitive number of points, how can that be if the line y=2 is an asymptote?
 
Ummm, I just noticed that the curve in your example does not intersect, but is rather tangent to y=2 infinitely many times. So, to be on the safe side, you should use my example.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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