Can a Magnet Slide Frictionlessly in a Linear Induction Flashlight?

AI Thread Summary
The discussion explores the feasibility of using a tube magnet sliding down a rod magnet to achieve a frictionless motion in a linear induction flashlight. The proposed design involves a tube magnet with an S polarity sliding down the S end of a rod magnet, theoretically allowing for equal repulsion and frictionless movement. However, concerns are raised about the effectiveness of this setup, particularly regarding the magnetic field strength diminishing with distance from the rod's end. Additionally, alternative methods to reduce friction are suggested, indicating that the proposed concept may not be the most efficient solution. Overall, while the idea is intriguing, practical challenges and better alternatives exist.
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I am attempting to build a linear induction flashlight. I was wondering if the concept below could be used to make the magnet slide down a pole inside a coil with no friction. The interior of a tube magnet with an S polarity would slide down the S end of a rod magnet, that way the inside of the tube would be equally repelled on all sides making the fall frictionless. Could this concept work? Also, would this continuous interaction between the magnets cause either of the magnets to become demagnetized if a neodymium magnet is used? Is there an easier way to create a frictionless fall? Any advice at all on how to make this work? (the tube magnet would not be a monopole) (sorry for any misused terms)
 

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Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 
Can you explain this to me a little bit more?
 
I was wondering if the concept below could be used to make the magnet slide down a pole inside a coil with no friction. The interior of a tube magnet with an S polarity would slide down the S end of a rod magnet, that way the inside of the tube would be equally repelled on all sides making the fall frictionless.

As drawn you don't have a south pole on the sides of the pole, only on the bottom end. If you try and fix that by arranging a lot of little magnets radially to make a pole that is S on the outside and N on the inside you will find that the further from the end you get the weaker the effect. At any significant distance from the end there will be no field. There are easier ways to reduce friction.
 
I was using the Smith chart to determine the input impedance of a transmission line that has a reflection from the load. One can do this if one knows the characteristic impedance Zo, the degree of mismatch of the load ZL and the length of the transmission line in wavelengths. However, my question is: Consider the input impedance of a wave which appears back at the source after reflection from the load and has traveled for some fraction of a wavelength. The impedance of this wave as it...

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