Can a Particle with Rest Mass Travel at the Speed of Light?

Qyzren
Messages
41
Reaction score
0
What is the rest mass m of a particle traveling with the speed of light in the laboratory frame?

i believe m = (E² - (pc)²)^.5 / c² is the correct equation to use?
as velocity goes up, so does energy and momentum? so when velocity is at speed of light, E = infinity and momentum = infinity? so we have infinity - infinity on the numerator? so this gives mass = 0? is any of this correct? thanks for help.
 
Physics news on Phys.org
The answer turns out to be correct, but the method is not. For one thing, you can not simply subtract off infinities in the manner that you just did.

What is the formula for the relativistic energy of a particle of rest mass, m? Write this down. Now if v=c, this gives you the result you (incompletely) stated above, namely that E = infinity, unless _______ (fill this in).

Ask yourself: Is it physical for a particle to be given an infinite amount of energy?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top