- #1
Can Angular Momentum Change Direction When a Wheel is Flipped Over?
- Thread starter tukms
- Start date
- #2
tiny-tim
Science Advisor
Homework Helper
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hi tukms! 
the wheel is rotating clockwise, then the student turns it over so that it's rotating anti-clockwise
so its angular momentum has changed (in fact, it's reversed)
from conservation of angular momentum, that change must be balanced by an equal change in the angular momentum of the student.
the wheel is rotating clockwise, then the student turns it over so that it's rotating anti-clockwise
so its angular momentum has changed (in fact, it's reversed)
from conservation of angular momentum, that change must be balanced by an equal change in the angular momentum of the student.
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure.
After the equation (4.50) it says
"It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)"
I still don't understand the figure :(
Here is...
Boundary conditions:
The derived Dirichlet and Neumann boundary conditions
In terms of the magnetic scalar potential:
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself.
Part (a) is quite easy. We get
$$\sigma_1 = 2\lambda, \mathbf{v}_1 =
\begin{pmatrix}
0 \\
0 \\
1
\end{pmatrix}
\sigma_2 = \lambda, \mathbf{v}_2 =
\begin{pmatrix}
1/\sqrt{2} \\
1/\sqrt{2} \\
0
\end{pmatrix}
\sigma_3 = -\lambda, \mathbf{v}_3 =
\begin{pmatrix}
1/\sqrt{2} \\
-1/\sqrt{2} \\
0
\end{pmatrix}
$$
There are two ways...
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