How Do You Calculate Frequency and Period in ASK Modulation?

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The discussion focuses on calculating the frequency and period of a signal that repeats 40,000 times in one minute. The frequency is determined to be 666.66 Hz, calculated by dividing 40,000 by 60 seconds. The period, which is the reciprocal of frequency, is confirmed to be 0.001 seconds. Participants clarify the relationship between frequency, period, baud rate, and bit rate in the context of Amplitude Shift Keying (ASK). The calculations and concepts are affirmed as correct, providing clarity on the topic.
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this is the ex:
What is the frequency in Hertz (cycles per second) of a signal that repeats 40,000 times within one minute? What is the period of the signal? (10 points)


i think the baud rate is 666.66
the same i the bit rate 666.66 in (ASK) Amplitude shift Keying.

I know that in (ASK) frequency and phase remain constant while only the amplitude change.

But i don't Know how to calculate the frequency and the phase.

can anybody help me?
 
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The frequency is defined as the number of cycles per second. 40 000 times per minute is how many cycles per second? A trivial calculation, no?

The period is the time per cycle, which, as I'm sure you can see, is the reciprocal of the frequency.

What does all this stuff about baud rate and bit rate have to do with anything, by the way?
 
cepheid said:
The frequency is defined as the number of cycles per second. 40 000 times per minute is how many cycles per second? A trivial calculation, no?

The period is the time per cycle, which, as I'm sure you can see, is the reciprocal of the frequency.

What does all this stuff about baud rate and bit rate have to do with anything, by the way?


you said that the frequency is 40000/60=666.66??
 
Nope, you said that. :wink: But that is correct, and hopefully is based on the hint I gave. I mean, if you have 40 000 cycles in a minute, a second is only one sixtieth of that time interval, so it stands to reason that in a second you have only one sixtieth the number of cycles. I hope that clears up why your calculation is correct.
 
cepheid said:
Nope, you said that. :wink: But that is correct, and hopefully is based on the hint I gave. I mean, if you have 40 000 cycles in a minute, a second is only one sixtieth of that time interval, so it stands to reason that in a second you have only one sixtieth the number of cycles. I hope that clears up why your calculation is correct.


ok thanks

and the period is T=1/666.66 = 0.001SEC
IS THAT TRUE?

THANKS AGAIN
 

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