Can AP Shell Pierce 2 Steel Plates? | Work Questions

  • Thread starter Thread starter Die4Physics
  • Start date Start date
  • Tags Tags
    Work
Click For Summary
The discussion revolves around whether an armor-piercing shell (AP) can penetrate two steel plates given its initial speed of 1800 m/s and a reduced speed of 1200 m/s after the first plate. The main concern is the reduction in speed after each penetration and how to calculate the kinetic energy (Ek) using the formula Ek = 1/2 mv² to determine if it can pierce the second plate. Participants emphasize the importance of showing calculations and working through the problem independently, as per forum rules. The conversation highlights the need for understanding the physics of motion and energy in this context. Overall, the inquiry seeks clarity on the mechanics of armor penetration.
Die4Physics
Messages
1
Reaction score
0
About Work Questions!

With the initial speed of 1800ms-1, AP(Armor Piercing Shell) after piercing through the 1st steel plate its speed is 1200ms-1. Can it pierces through the second steel plate? I know what you mean but the problem I encounter is I am not sure whether the speed will reduce by 600ms-1 every piercing? And I don't know how can i show that it can or it can't pierces through the 2nd steel plate? On my understanding this is a horizontal motion so there wouldn't be any Ep. There will only be Ek and with the formula Ek=1/2mv2 how i can show will it pierces through the 2nd plate.
Your help will be much appreciate!
Thank you!
 
Last edited:
Physics news on Phys.org


Please show your work... we on PF can't just help without you working out on your own as per the rules.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 88 ·
3
Replies
88
Views
9K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
6K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
2
Views
2K