Can Calculating Ocean Bottom Temperature Enable Efficient Heat Engine Operation?

AI Thread Summary
Calculating ocean bottom temperature is crucial for optimizing heat engine performance, particularly in solar-powered systems. The average solar irradiance is noted as 240W/m², with a surface water temperature of 25ºC. The discussion highlights the importance of efficiency in determining the temperature at the ocean's bottom to achieve a power output of 0.1MW over a surface area of 10,000 m². Participants emphasize the need to apply the Carnot efficiency concept to relate energy input and output effectively. Ultimately, the problem was resolved by confirming the use of efficiency and identifying the temperature at the bottom of the ocean.
ruiwp13
Messages
40
Reaction score
0

Homework Statement


A haet engine works based on the difference of the temperature at the top and bottom of the ocean. The machine is solar powered and the average solar irradiance is 240W/m^2 and the temperature at the surface of the water is 25ºC. Calculate the temperature at the bottom of the ocean so that the machine debits a power of 0.1MW to a surface area of 10^4 m^2.

Homework Equations


Q=σ*A*T^4(surface)


The Attempt at a Solution


I am stuck in this one... I don't know if it is possible for you to give me some hint. I'm not sure if I need to find the efficiency here, but I'll probably will need it to get the heat at the bottom and maybe trough there get the temperature.
 
Physics news on Phys.org
the machine debits a power of 0.1MW to a surface area of 10^4 m^2.
is sure a roundabout way to phrase what i take to be power balance...

Do you suppose he means "delivers useful work of 10 watts/m2 at Carnot efficiency?

If so, it seems to me he's given you both efficiency and Thot .
 
  • Like
Likes 1 person
My bet is that is about efficiency only - you are given energy input and energy output. See if you can follow from here.

Edit: Jim was slightly faster, and we definitely said the same thing.
 
  • Like
Likes 1 person
First I want to thank you both for the answer. Yes, I concluded that it was supposed to use the efficiency and I was given Th being Tc the temperature at the bottom. It's done!
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top