Can Calculating Ocean Bottom Temperature Enable Efficient Heat Engine Operation?

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Discussion Overview

The discussion revolves around a homework problem related to calculating the temperature at the bottom of the ocean for a solar-powered heat engine, which operates based on the temperature difference between the ocean's surface and its bottom. The context includes theoretical considerations of efficiency and power balance in heat engines.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a homework statement involving the calculation of ocean bottom temperature based on given parameters, including solar irradiance and surface temperature.
  • Another participant interprets the problem as a power balance and questions whether the stated power output is meant to imply a specific efficiency at Carnot efficiency.
  • A third participant suggests that the problem primarily concerns efficiency, indicating that both energy input and output are provided.
  • A later reply confirms the understanding that the efficiency is to be used in conjunction with the temperatures to solve the problem.

Areas of Agreement / Disagreement

Participants generally agree on the need to consider efficiency in the calculations, but there is some ambiguity regarding the interpretation of the power output and its implications for the problem.

Contextual Notes

There are unresolved assumptions regarding the definitions of efficiency and the specific conditions under which the calculations are to be made, as well as the potential need for additional information to fully solve the problem.

ruiwp13
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Homework Statement


A haet engine works based on the difference of the temperature at the top and bottom of the ocean. The machine is solar powered and the average solar irradiance is 240W/m^2 and the temperature at the surface of the water is 25ºC. Calculate the temperature at the bottom of the ocean so that the machine debits a power of 0.1MW to a surface area of 10^4 m^2.

Homework Equations


Q=σ*A*T^4(surface)


The Attempt at a Solution


I am stuck in this one... I don't know if it is possible for you to give me some hint. I'm not sure if I need to find the efficiency here, but I'll probably will need it to get the heat at the bottom and maybe trough there get the temperature.
 
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the machine debits a power of 0.1MW to a surface area of 10^4 m^2.
is sure a roundabout way to phrase what i take to be power balance...

Do you suppose he means "delivers useful work of 10 watts/m2 at Carnot efficiency?

If so, it seems to me he's given you both efficiency and Thot .
 
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My bet is that is about efficiency only - you are given energy input and energy output. See if you can follow from here.

Edit: Jim was slightly faster, and we definitely said the same thing.
 
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First I want to thank you both for the answer. Yes, I concluded that it was supposed to use the efficiency and I was given Th being Tc the temperature at the bottom. It's done!
 

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