Can someone check if i'm doing this right?

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Dubbie is moving towards a mirror at 3.5 m/s, resulting in an image speed of 7.0 m/s relative to Dubbie. When Dubbie walks away from the mirror at an angle of 30 degrees, the relevant calculation involves finding the velocity component normal to the mirror's surface. The correct approach is to use the sine function to determine this component, which results in a speed of 1.75 m/s when calculated with the sine of 30 degrees. It's suggested to visualize the scenario with a diagram for clarity. Understanding the normal velocity is crucial for accurately determining the image speed.
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Dubbie is moving directly along a normal line toward a plain mirror at a speed of 3.5 m/s, what is the speed of the image relative to Dubbie?

v Dubbie + v mirror = v image
3.5 m/s + 3.5 m/s = 7.0 m/s


What is the speed of the image, relative to Dubbie, if Dubbie walk away from the mirror surface at 3.5 m/s at an angle of 300 to the mirror surface?

Given:
θ = 300
v= 3.5 m/s

x/v= sinθ
x/(3.5 m/s) = sin300
x = [(3.5 m/s) sin300]
x = 1.75 m/s
 
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Sorry.. should be sin 30 deg
 
I'm not sure what you're doing for part 2. Have you drawn a diagram of what is happening and what you need to find out? Basically you want to find the velocity normal to the surface of the mirror and double that.
 
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