Canoe Movement Calculations: 45kg Woman in a 60kg Canoe

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In the scenario of a 45kg woman walking in a 60kg canoe, the system's center of mass remains unchanged since both the woman and canoe are initially at rest. As she moves from one end of the canoe to the other, the canoe will shift in the opposite direction due to the conservation of momentum. The distance the canoe moves can be calculated using the principle of action-reaction, where the movement of the woman causes an equal and opposite movement of the canoe. The time taken for her to walk the distance is the same for both the woman and the canoe, allowing for straightforward calculations of their respective distances moved. Ultimately, the canoe's movement can be determined by analyzing the distances covered by both the woman and the canoe relative to their masses.
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i'm having a problem with this one:
45kg woman is in a 60kg canoe of length 5m. They are initially at rest. she walks from a point 1m from the end to a point 1m from the other end where she stops. If resistance and the motion of the canoe in the water are ignored, how far does the canoe move during the process.

I thought this was a center of mass problem, but the center of mass doesn't change because the woman begins at rest. i don't know where to start...
 
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How about conservation of momentum?

Hint: the magnitude of velocity (speed) = distance/time, and the time is the same.

Action-reaction.
 
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