Capacitor Connections and Charge Conservation

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SUMMARY

The discussion focuses on the behavior of two capacitors, C1 (2.4µF at 880V) and C2 (4.0µF at 560V), when connected in different configurations. When the positive plates are connected together, charge conservation allows for the calculation of final voltage and charge on each capacitor using the formula Q=CV. In contrast, connecting the positive plate of one capacitor to the negative plate of the other results in a different final voltage and charge distribution, necessitating an understanding of series and parallel configurations. The total charge remains conserved throughout both scenarios.

PREREQUISITES
  • Understanding of capacitor charge and voltage relationships (Q=CV)
  • Knowledge of series and parallel capacitor configurations
  • Familiarity with charge conservation principles
  • Basic electrical circuit analysis skills
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  • Learn about calculating equivalent capacitance for capacitors in series and parallel
  • Explore the effects of connecting capacitors with different initial voltages
  • Investigate practical applications of capacitors in electronic circuits
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Homework Statement


a capacitor C1 2.4uF charged to a voltage of 880V and a second capacitor C2 4.0uF charged to 560V. They are disconnected from their batteries and their positive plated and connected together, and their negative plated are connected together. What will the final voltage and charge on each be after a long time? They are then connected negative to positive..and same question as before.


Homework Equations


Q=CV


The Attempt at a Solution


I don't really have a clue. However, I found the charge on each capacitor initially then added them together, and found the percent for each capacitor (C1/(C1+C2)) and times it by the total charge. Does that even make sense? because the answer was right. Are you able to add the capacitors in any way? are they in series or parallel? the voltages of them were the same as if they were in parallel. AH!
 
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Find the charge Q1 on C1 and Q2 on C2.

The total charge has to be conserved.

Then find the combined capacitance in parallel, and find the voltage based on the total charge and effective capacitance.
 
Astronuc said:
Find the charge Q1 on C1 and Q2 on C2.

The total charge has to be conserved.

Then find the combined capacitance in parallel, and find the voltage based on the total charge and effective capacitance.

This works for the first case where the 2 positive ends are connected. In the second case where the positive is connected to the negative of the other it doesn't..whether you add the capacitances in parallel or series?! The voltage and charge on each is much smaller.
 

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