Cartesian to Cylindrical coordinates?

shreddinglicks
Messages
225
Reaction score
7

Homework Statement


I want to convert R = xi + yj + zk into cylindrical coordinates and get the acceleration in cylindrical coordinates.

Homework Equations


Inline31.gif
Inline32.gif
Inline33.gif

Inline34.gif
Inline35.gif
Inline36.gif

Inline37.gif
Inline38.gif
z

The Attempt at a Solution


I input the equations listed into R giving me:

R =
Inline33.gif
i +
Inline36.gif
j + z k

Apply chain rule twice:

Inline209.gif


The final answer is:

Inline212.gif


How do I get this final answer? It looks like the terms with sin were dropped. How does this happen?
 

Attachments

  • Inline31.gif
    Inline31.gif
    173 bytes · Views: 756
  • Inline33.gif
    Inline33.gif
    1.1 KB · Views: 509
  • Inline38.gif
    Inline38.gif
    162 bytes · Views: 498
  • Inline37.gif
    Inline37.gif
    273 bytes · Views: 480
  • Inline36.gif
    Inline36.gif
    1 KB · Views: 523
  • Inline35.gif
    Inline35.gif
    162 bytes · Views: 496
  • Inline34.gif
    Inline34.gif
    277 bytes · Views: 464
  • Inline33.gif
    Inline33.gif
    1.1 KB · Views: 504
  • Inline32.gif
    Inline32.gif
    162 bytes · Views: 720
  • Inline212.gif
    Inline212.gif
    2 KB · Views: 469
  • Inline209.gif
    Inline209.gif
    3.2 KB · Views: 478
  • Inline36.gif
    Inline36.gif
    1 KB · Views: 464
Physics news on Phys.org
Your result is an expression for the acceleration using the Cartesian vector basis (i.e., you are showing the Cartesian components expressed in terms of the cylinder coordinates). You need to relate this to the vector components using the cylinder coordinate basis vectors.
 
Orodruin said:
Your result is an expression for the acceleration using the Cartesian vector basis (i.e., you are showing the Cartesian components expressed in terms of the cylinder coordinates). You need to relate this to the vector components using the cylinder coordinate basis vectors.

I don't think I understand. By basis you mean the unit vectors in rHat, thetaHat, zHat?
 
Yes, that is the basis that you should be using to express your vector as done in the quoted result.
 
Orodruin said:
Yes, that is the basis that you should be using to express your vector as done in the quoted result.

So I have:

Inline69.gif
Inline70.gif
Inline71.gif

Inline72.gif
Inline73.gif
Inline74.gif

Inline75.gif
Inline76.gif
Inline77.gif


I don't see how I replace i,j,k with these to get the answer.
 

Attachments

  • Inline76.gif
    Inline76.gif
    170 bytes · Views: 439
  • Inline75.gif
    Inline75.gif
    289 bytes · Views: 433
  • Inline74.gif
    Inline74.gif
    2 KB · Views: 402
  • Inline73.gif
    Inline73.gif
    170 bytes · Views: 391
  • Inline72.gif
    Inline72.gif
    516 bytes · Views: 404
  • Inline71.gif
    Inline71.gif
    1.9 KB · Views: 416
  • Inline70.gif
    Inline70.gif
    170 bytes · Views: 406
  • Inline69.gif
    Inline69.gif
    283 bytes · Views: 420
  • Inline77.gif
    Inline77.gif
    1.6 KB · Views: 401
You have a result for your vector. You need to express it as a linear combination of the vector basis, i.e., you need to find ##v_r##, ##v_\theta## and ##v_z## such that
$$
\vec v = v_r \hat r + v_\theta \hat \theta + v_z \hat z.
$$
Since you have three components, this is a system of three equations for three unknowns.
 
Orodruin said:
You have a result for your vector. You need to express it as a linear combination of the vector basis, i.e., you need to find ##v_r##, ##v_\theta## and ##v_z## such that
$$
\vec v = v_r \hat r + v_\theta \hat \theta + v_z \hat z.
$$
Since you have three components, this is a system of three equations for three unknowns.
I see it. Thanks!
 
Back
Top