- #1
kliide
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Hi, first post. I'm a math/physics, uh, underachiever and I'm looking for more resources on Centrifuges. I apologize in advance for the inaccuracy of my use of physics terminology.
I'm interested in finding a formula that calculates both the amount of force and angle of force of tangential inertia in a centrifuge. I've found many explanations involving centrifuges where the tangential inertia is restricted to 2 dimensions and described in terms of the tangential inertia created by rotary motion, but only on a horizontal plane.
Here's my problem: what I'm trying to find out is how tangential inertia would apply in a 3 dimensional system where the rotating mass was fixed to the central hub below the height at which the rotating mass' center of gravity/mass would be optimally distant from the center of the rotating mass. I guess what I'm trying to describe is like a pole with 2 tether balls attached by equal length strings.
Just from observation, I can see that once the pole begins rotating at an appropriate speed, the tether balls are pulled outward until they lie on a plane with the point at which they were fixed. I'm guessing that in this case the vertical trajectory would curve with the radius of the string until reaching a point on a plane with where they were tethered to the pole. I'm also guessing that the tangential inertia would be restricted to a 2 dimensional horizontal plane and the vertical component of movement was only a result of being fixed by a string.
Ok, now for the actual question. If the tether balls were fixed at a 45 degree angle below the plane at which they were fixed to the pole (using a steel rod instead of string), what would the resulting angle of tangential inertia be in this configuration? Is there a vertical component to the inertia in a centrifuge arrangement where the center of gravity/mass of the rotating mass lies below the point at which the rotating mass is fixed to the pole? If there is a vertical component to this inertia, then how is it defined?
Thanks in advance,
Jon
I'm interested in finding a formula that calculates both the amount of force and angle of force of tangential inertia in a centrifuge. I've found many explanations involving centrifuges where the tangential inertia is restricted to 2 dimensions and described in terms of the tangential inertia created by rotary motion, but only on a horizontal plane.
Here's my problem: what I'm trying to find out is how tangential inertia would apply in a 3 dimensional system where the rotating mass was fixed to the central hub below the height at which the rotating mass' center of gravity/mass would be optimally distant from the center of the rotating mass. I guess what I'm trying to describe is like a pole with 2 tether balls attached by equal length strings.
Just from observation, I can see that once the pole begins rotating at an appropriate speed, the tether balls are pulled outward until they lie on a plane with the point at which they were fixed. I'm guessing that in this case the vertical trajectory would curve with the radius of the string until reaching a point on a plane with where they were tethered to the pole. I'm also guessing that the tangential inertia would be restricted to a 2 dimensional horizontal plane and the vertical component of movement was only a result of being fixed by a string.
Ok, now for the actual question. If the tether balls were fixed at a 45 degree angle below the plane at which they were fixed to the pole (using a steel rod instead of string), what would the resulting angle of tangential inertia be in this configuration? Is there a vertical component to the inertia in a centrifuge arrangement where the center of gravity/mass of the rotating mass lies below the point at which the rotating mass is fixed to the pole? If there is a vertical component to this inertia, then how is it defined?
Thanks in advance,
Jon