Centripetal Force Calculation for Hanging Partner

AI Thread Summary
The discussion centers on calculating the centripetal force required for a man hanging upside down while holding a partner weighing 475 N, moving in a circular path with a radius of 6.5 m at a speed of 4.0 m/s. The calculations provided yield a centripetal force of 119.31 N, leading to a total force of 594.31 N when accounting for the partner's weight. There is a mention of differing information from a professor and a TA regarding access to even answers for quiz preparation. The original poster expresses confusion over the TA's response and seeks confirmation of their calculations. The thread highlights the importance of understanding Newton's second law in relation to centripetal motion.
jehan4141
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Will you please tell me if my work is correct? My professor said to ask my TA for the even answers in prep for my quizzes on Fridays, but the TA told me there is no way to access even answers...somebody is not being honest. Anyhow, any help would be great. Thank you!

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In Figure 5.8 the man hanging upside down is holding a partner who weighs 475 N. Assume that the partner moves on a circle that has a radius of 6.50 m. At a swinging speed of 4.00 m/s, what force must the man apply to his partner in the straight-down position?

Wp = 475 N
Mp = 475/9.8 = 48.46938776 kg
r = 6.5 m
V = 4 m/s

FC = mv2 / r = (48.469)(42 / 6.5 = 119.31 N
Ftotal = FC + Wp = 119.31 + 475 = 594.31 N
 
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Correct.
But I would have started from Newton's 2nd law:
resultant force = m x acc (towards centre of circle)
Fpartner - wt of hanging man = m x centripetal acc
 
Thank you and for the tip!
 

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