Centripetal/Projectile Motion: Proof of Formulas for v^2=mgy

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The discussion revolves around proving the formula v^2 = mgy in the context of centripetal and projectile motion. A scenario is presented where a ball on a string swings through a quarter circle, and upon breaking, it launches horizontally. The participants highlight the need to prove that v^2 = 2gR, with one user expressing difficulty in deriving the correct formula using kinematic equations. Another user suggests using conservation of energy as an effective approach to solve the problem. The conversation emphasizes the importance of proper problem posting and the application of fundamental physics principles.
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from the second question in the link, I've been asked to figure out how to proof some of the formulas. Could someone please help me? I tried using some formulas but I keep getting stuck. If it doesn't show, then could someone please help me proof the formula v^2=mgy

file:///C:/Documents%20and%20Settings/Jenny/Desktop/physics%20assignment2.htm
 
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none of us can access a file on your computer, you're going to have to post the question manually.
 
A ball on a string is released from rest with the string horizontal and swings through a quarter circle of radius R. At the bottom of the swing the string breaks and the ball is launched horizontally with speed v. The bottom of the swing is a distance 2R above the floor and the ball lands on the floor a distance d away. I'm using v for velocity, R for radius, and g gravity and a for accelaration
We have to prove that v^2=2gR

I used the formula v^2y-v^2oy=2ay(y-yo)
My final answer was -v^2=4gR...something's wrong here because i need help
 
First: This should be posted in Homework Help.

Second: You can use conservation of energy here to solve it.
 
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