Chain rule proof help me dunno what's wrong

Andrax
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Homework Statement


this is kinda funny I've been strugglnig with the proof for 3 hours straight today
long story short(<--sorry couldn't find the best way t o say this ) i made it to this statement
lim(x->a) g(x) if this is equal to g(x) then my proof is done
lim(x->a) f(a) if this is equal to f(x) then my proof is done
what's on my mind : this is obviously NOT correct ,after 3 hours of pain i decided to check the txtbook found everything that I've doneto this part and they just write
lim(x->a) g(x)=g(x) and lim(x->a) f(a)=f(x) vthis made me pretty mad i have no idea how they've done this , i was good at limits i have no idea how is this correct if someone can help explain it to me please

forgot to metion i don't think this is important though they use h instead of x-a
chain rule = d/dx (f*g) = df/dxf*g+dg/dxg*f

Homework Equations


without reading the above why lim(x->a) g(x)=g(x)
and why lim(x->a) f(a)=f(x)

The Attempt at a Solution


what I've said up
 
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##\lim_{x\to a}g(x)## is not equal to g(x). Note that this wouldn't even make sense, since x is a dummy variable in ##\lim_{x\to a}g(x)##. This expression means the same thing as ##\lim_{t\to a}g(t)##. It's equal to g(a) if and only if g is continuous at a. (Note that if g is differentiable at a, it is also continuous at a).
 
Oh i totally missed this part g is actually continuous at a thanks
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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