Change of variables for double integrals

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SUMMARY

The discussion focuses on using a change of variables to determine the area of the region R bounded by the curves y=x², y=4x², y=√x, and y=(1/2)√x. The proposed transformation involves setting y=ux² and y=v√x, leading to the boundaries u=1, u=4, v=1, and v=1/2. This method effectively simplifies the integration process by transforming the original variables into a more manageable form.

PREREQUISITES
  • Understanding of double integrals in calculus
  • Familiarity with change of variables in integration
  • Knowledge of bounding curves and regions in the Cartesian plane
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the method of change of variables in double integrals
  • Learn about Jacobians and their role in transformations
  • Explore examples of area calculations using different variable transformations
  • Investigate the implications of inverse transformations in integration
USEFUL FOR

Students and educators in calculus, mathematicians focusing on integration techniques, and anyone interested in advanced methods for calculating areas in multivariable calculus.

jonnyboy
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Homework Statement


Use a suitable change of variable to find the area of the region R bounded by [tex]y=x^2, y=4x^2, y=\sqrt{x}, y=\frac{1}{2}\sqrt{x}[/tex]


2. The attempt at a solution
I am trying to first find the inverse transformations {u & v =?
 
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jonnyboy said:

Homework Statement


Use a suitable change of variable to find the area of the region R bounded by [tex]y=x^2, y=4x^2, y=\sqrt{x}, y=\frac{1}{2}\sqrt{x}[/tex]


2. The attempt at a solution
I am trying to first find the inverse transformations {u & v =?
The obvious thing to do would be to set y= ux2 and y= v[itex]\sqrt{x}[/itex]= vx1/2. That way, R is bounded by u= 1, u= 4, v= 1 and v= 1/2. u= y/x2 and v= yx-1/2.
 

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