Changing limits of integration question

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SUMMARY

The integral of the function \(\int \frac{A \cos x + B \sin x + C}{a \cos x + b \sin x + c} \, dx\) with limits from \(-\pi\) to \(\pi\) can be evaluated by recognizing that the function is periodic. The periodicity is confirmed since it is a combination of sine and cosine functions, both of which have a period of \(2\pi\). Therefore, it is valid to change the limits of integration to \(0\) and \(2\pi\) without affecting the result. However, caution is advised as the denominator may become zero for certain values of \(x\), which could complicate the integration process.

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Homework Statement


Evaluate

\int(Acosx + Bsinx + C)/(acosx + bsinx +c) dx

where the limits of integration are -π and π


Homework Equations





The Attempt at a Solution


Hi everyone,

My question is: is the function periodic (I'm guessing it is, as it's a combination of sin, cos and constants?)
and, if so, is its period 2π (as sin and cos are of period 2π
and, if so, can we change the limits of integration to 0 and 2π without changing anything else (this would make sense to me)?

Can we do this in general for periodic functions - shift the limits of integration on by a certain number if they are the period?

Thanks for any help

P.S. I know you're supposed to show your work, but I can't really think what else to say!
 
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These are some easy functions you might want to check out first, in order to understand your own questions.
to your first question: sin(x)+sin(pi*x) 's period=? . by the way, f is period iff f(x)=f(x+T) for some T.
to your second: sin(x)/cos(x)=tan(x)'s period=?
to your third: the denominator can be zero for some x, and therefore I guess you might not be able to integrate it over an arbitrary interval. for example, tan(x) is not integrable over [0,pi/2)
 

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