Charge and Electric Field Intensity

  • #1
If there are two bodies, such as a sphere and a thin rod (each with exactly the same charge), why does the sphere have a greater electric field intensity? Are there any other variables that influence the electric field intensity if the charge is not an ultimate dependent factor?

If the charges are the same, would the intensity difference have anything to do with the force, work, or distance involved?
 

Answers and Replies

  • #2
ranger
Gold Member
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1
If there are two bodies, such as a sphere and a thin rod (each with exactly the same charge), why does the sphere have a greater electric field intensity? Are there any other variables that influence the electric field intensity if the charge is not an ultimate dependent factor?

If the charges are the same, would the intensity difference have anything to do with the force, work, or distance involved?

Well the answer to your question has to do with the surface. Particularly the curvature of the surface. Conductors at electrostatic equilibrium have stronger electric field where the surface is most curved.

Consider a flat surface, there are n charges (electrons). Being that they have a negative charge, they will repel each other. The repulsive force is directly parallel to the surface.

Now if we have n charges along a curved surface, the repulsive force is no longer parallel to the surface, but at an angle.

Do you get the idea whats happening here?
 
  • #3
Yes, I think I have a clearer idea now.
 

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