Charge and voltage of capacitors?

AI Thread Summary
The discussion focuses on calculating the charge and voltage across a set of capacitors with given values. Capacitors C1, C2, and C3 are each 16.0 µF, while C4 is 28.5 µF, with a known charge on C2 of 12.4 µC. The voltage across C1 and C2 is calculated to be 0.775 V, while the voltage across C3 and C4 is determined to be 1.55 V. The charges on C3 and C4 are then calculated as 24.8 µC and 44.175 µC, respectively. The discussion highlights the importance of conservation of charge in determining the relationships between the charges on the capacitors.
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Homework Statement



Suppose that C1 = C2 = C3 = 16.0 µF and C4 = 28.5 µF. If the charge on C2 is Q2 = 12.4 µC, determine the charge on each of the other capacitors, the voltage across each capacitor, and the voltage Vab across the entire combination.

http://i29.photobucket.com/albums/c261/gmmstr827/capacitor.jpg

Homework Equations



Q=CV

The Attempt at a Solution



C1=C2=C3=16.0 µF, C4=28.5 µF
Q2=12.4 µC

Note that V1=V2, V3=V4, and Q1=Q2

V2=Q2/C2
V2 = 12.4 µC / 16.0 µF
V1 = V2 = 0.775 V

Note that V3 = 2*V2

V3 = 2*0.775 V
V3 = 1.55 V

Q3=C3*V3
Q3 = 16.0 µF * 1.55 V
Q3 = 24.8 µC

Q4 = C4*V4
Q4 = 28.5 µF * 1.55 V
Q4 = 44.175 µC

Therefore
Q1 = Q2 = 12.4 µC
Q3 = 24.8 µC
Q4 = 44.175 µC
V1 = V2 = 0.775 V
V3 = V4 = 1.55 VIs that correct?
 
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You were doing fine until you ran up against Q4. Take a close look at what you've written.
 
gneill said:
You were doing fine until you ran up against Q4. Take a close look at what you've written.

Guess I didn't hit the Ctrl+C hard enough that time and pasted the previous thing. I fixed it. The numbers all work out though I believe?
 
V3≠v4

Use conservation of charge to find how Q4 is related to the other charges.
 
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