How Many Coulombs of Positive Charge Are in the Nuclei of 2.0 Mol of O2 Gas?

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To determine the total positive charge in the nuclei of 2.0 mol of O2 gas, one must consider that each O2 molecule contains two oxygen atoms. Using Avogadro's number, which is approximately 6.022 x 10^23, it is calculated that 2.0 mol of O2 contains about 12.046 x 10^23 oxygen atoms. Each oxygen atom has 8 protons, leading to a total of 96.368 x 10^23 protons in 2.0 mol of O2. The charge of a single proton is 1.6 x 10^-19 coulombs, resulting in a total positive charge of approximately 15.42 coulombs. Understanding that O2 is diatomic is crucial for accurate calculations.
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Homework Statement



Suppose you have 2.0 mol of O2gas.
How many coulombs of positive charge are contained in this gas in the atomic nuclei?


Homework Equations



q = Ne

The Attempt at a Solution



i guess i have to use the avogadros's number somehow. but not sure how does that fit in this equation
 
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rayhan619 said:
i guess i have to use the avogadros's number somehow. but not sure how does that fit in this equation

Yes you do. What is the definition of Avagadro's number? That gets you most of the way to the answer...
 
so we have 6.023*10^23 atoms in 1 mole.
so in 2 mole we have 6.023*10^23*2 = 12.046*10^23 proton
and the charge of each proton is 1.6*10^-19.
so total positive charge would be 1.6*10^-19*12.046*10^23 = 19.27*10^4
but that wasnt the right answer
 
rayhan619 said:
Suppose you have 2.0 mol of O2gas.
How many coulombs of positive charge are contained in this gas in the atomic nuclei?


Re-read the problem statement... :wink:
 
im sorry i don't get it.
if we use the above equation, then e = q/N = 2/6.023*10^23 = 0.33*10^-23
?
Im lost
 
rayhan619 said:
im sorry i don't get it.
if we use the above equation, then e = q/N = 2/6.023*10^23 = 0.33*10^-23
?
Im lost

The numbers you are using are for a monatomic gas. Oxygen gas is diatomic...
 

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