Charge density in cylinder with uniform charge

AI Thread Summary
The discussion revolves around calculating the electric field inside a uniformly charged non-conducting cylinder at a distance r = R/2 from its axis. The user applies Gauss's law but encounters a discrepancy in their final result. They derive the electric field as E = ρ/4ε0, while the expected answer is E = ρR/4ε0. The confusion stems from the distinction between volume and surface area in the application of Gauss's law. Clarification on the correct approach to determine the enclosed charge and the appropriate Gaussian surface is needed to resolve the issue.
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1. A charge density ρ (charge per unit volume) is distributed uniformly throughout a non-conducting cylinder of radius R. What is the magnitude of the electric field a distance r = R/2 from the cylinder's axis?

Homework Equations



E ∫dA = q(interior)/ε0[/B]3.

So I tried doing EA = (ρA)(v/V)/ε0 where v is the volume of the Gaussian surface and V is the volume of the cylinder

E = (ρ*(πR^2L/4πR^2L))/ε0
E = ρ/4ε0

However the answer is supposed to be E = ρR/4ε0

I'm not sure where I'm going wrong
 
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Check Gauss law once more: one is a volume (to determine q(interior) ) and the other is an area (of the surface).
 
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