Charge on a bead given the Electric Potential

AI Thread Summary
To solve for the charge on a positively charged glass bead given the potential difference, the user is considering using the relationship V = E * ds to find the electric field. They plan to apply the equation E = kq/r^2 to derive the charge. However, they are struggling to get the correct numerical results. The potential difference can be expressed using the formula PDiff = q/r1 - q/r2. Clarification on the approach and calculations is requested to ensure accuracy in solving the problem.
julianne
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I currently have this problem for homework:

A 1.80 -diameter glass bead is positively charged. The potential difference between a point 1.80 from the bead and a point 4.00 from the bead is 470 . What is the charge on the bead?

And I cannot seam to get it. First I thought that I should relate the fact that V=E*ds to find electric field and then solve for the charge with teh general equation E=kq/r^2.

Can anyone tell me if I am on the right track because I can't get the numbers to work.

Thank you for your help!
 
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Oh...and the measurements are all in milimeters!
 
Use PDiff=q/r_1-q/r_2.
 

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