Physics2341313
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Homework Statement
Consider the figure below, we need to find the charge on Q_0, both charges Q are negative. It is given that the net charge on Q_A is zero.
The figure of the problem is attached.
The Attempt at a Solution
I understand how to get the solution except for one part. I'm just going to write F_x and F_y below to denote the forces components as the numbers aren't relevant (I don't think?) for my question.
I understand that we can discard the constant 1/4\pi\epsilon_0 or k whichever is preferred and that we can get rid of the a^2 terms in denominators when taking the radius and likewise for sin/cos for the respective components.
The solution is Q_0 Q/8 = \sqrt {F_x^2 + F_y^2}.
Now the solution is obtained by Q_0 = 8 * \sqrt {F_x^2 + F_y^2}
Why is Q discarded here? I just don't see where it goes mathematically.. it just kind of "disappears". Is it discarded because it is stated that the net force caused by this charge is negligible?
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