Charge on q from other charges given net force is zero

AI Thread Summary
The discussion revolves around determining the charge on Q_0 given that the net force on Q_A is zero, with both charges Q being negative. Participants express confusion about why certain terms, like Q, seem to disappear from the equations and whether this is due to the net force being negligible. Clarifications are sought regarding the components of force (F_x and F_y) and the notation used in the calculations. There is also a suggestion to utilize symmetry in the problem to simplify the analysis, although some participants struggle with identifying symmetrical relationships in charge configurations. Overall, the conversation highlights the complexities of understanding force interactions and the importance of clear notation in physics problems.
Physics2341313
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Homework Statement



Consider the figure below, we need to find the charge on Q_0, both charges Q are negative. It is given that the net charge on Q_A is zero.

The figure of the problem is attached.

The Attempt at a Solution



I understand how to get the solution except for one part. I'm just going to write F_x and F_y below to denote the forces components as the numbers aren't relevant (I don't think?) for my question.

I understand that we can discard the constant 1/4\pi\epsilon_0 or k whichever is preferred and that we can get rid of the a^2 terms in denominators when taking the radius and likewise for sin/cos for the respective components.

The solution is Q_0 Q/8 = \sqrt {F_x^2 + F_y^2}.

Now the solution is obtained by Q_0 = 8 * \sqrt {F_x^2 + F_y^2}

Why is Q discarded here? I just don't see where it goes mathematically.. it just kind of "disappears". Is it discarded because it is stated that the net force caused by this charge is negligible?
 

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Physics2341313 said:
It is given that the net charge on QA is zero.
That doesn't mean anything. Do you mean the net force on QA is zero, or the potential at QA is zero?

Please clarify what Fx and Fy represent.
I don't understand why you would have Q0Q in an equation. You don't care about any forces acting between Q0 and the two Q charges. Did you mean Q0QA?
 
The units on the solution aren't consistent. They show that (units of electric charge)^2 = force.
 
I didnt understand where the Q went until I reworked it and yes you're right. Is the below correct? It gives me the correct answer but as far as best way to solve technique etc goes not sure its close to good.

My notation could probably use some work... I realize I could have forgotten about the Q_0 components but split this up for practice breaking components up anyways.

I attached the work instead of trying to type tons of latex and mess it up
 

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Physics2341313 said:
I didnt understand where the Q went until I reworked it and yes you're right. Is the below correct? It gives me the correct answer but as far as best way to solve technique etc goes not sure its close to good.

My notation could probably use some work... I realize I could have forgotten about the Q_0 components but split this up for practice breaking components up anyways.

I attached the work instead of trying to type tons of latex and mess it up
It's probably neater to use the symmetry. Just use the components parallel to the line x+y=0.
 
I'm not sure what you mean? I'm very bad at using symmetry doing these types of problems typically takes me ages as I can't identify the symmetry / relations correctly in square arrays of charge etc. Could you explain what you mean?
 
Physics2341313 said:
I'm not sure what you mean? I'm very bad at using symmetry doing these types of problems typically takes me ages as I can't identify the symmetry / relations correctly in square arrays of charge etc. Could you explain what you mean?
Where could you put a straight line through the diagram so that the portions on eithe side are mirror images of each other? Hint: two of the charges are unique, so it must pass through each of those.
 
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