Charge passing through a cross section for a time varying current

AI Thread Summary
The current in the wire is described by the equation I(t) = 6.00 A + (4.80 A/s)t. To find the total charge passing through a cross section from t = 0.00 s to t = 3.00 s, the integral of the current over time is used, leading to the equation q = ∫I dt. Initially, an incorrect calculation resulted in q = 75.6 C, but after reevaluating the integral, the correct charge is determined to be q = 39.6 C. The discussion highlights the importance of accurately setting up the integral and checking calculations. Ultimately, the user corrected their mistake and confirmed the right answer.
superslow991
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Homework Statement


The current in a wire varies with time according to the equation I(t) = 6.00 A + (4.80 A/s)t, where t is in seconds. How many coulombs of charge pass a cross section of the wire in the time period between t = 0.00 s and 3.00 s

Homework Equations


I=dq/dt

The Attempt at a Solution


So since were calculating the current, i solved for q=(integral)I*dt which was the integral from 0 to 3 (6.00A+(4.80)t and got the answer q = 75.6 which is wrong. The answer is q= 39.6.
I know the problem lies in the math but I am not sure where I am wrong.
 
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Can you write out your steps in performing your integral so we can see where you made a mistake.

Edit: Maybe you attempted to post a picture and it didn't show up.
 
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TomHart said:
Can you write out your steps in performing your integral so we can see where you made a mistake.

Edit: Maybe you attempted to post a picture and it didn't show up.
Actually i think i input my equation wrong i got the right answer
 
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