Checking my work - Displacement

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    Displacement Work
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The total displacement of the boat is calculated by considering its final position relative to the starting point. After traveling 100 km north and then 40 km north, the boat is 140 km north. It then travels 80 km south, resulting in a final position of 60 km north of the starting point. Thus, the correct displacement is 60 km north. This calculation clarifies the distinction between distance traveled and displacement, which includes direction.
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A boat which travels 100km[N], then 40km[N], and finally 80km . The entire trip takes 6.5 hours.
Calculate the total displacement of the boat

d = d2-d1
d = (-80) - 140
d = -220
d = 220km

Just want to make sure this is correct.

Thanks
 
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kristy_vincen said:
A boat which travels 100km[N], then 40km[N], and finally 80km . The entire trip takes 6.5 hours.
Calculate the total displacement of the boat

d = d2-d1
d = (-80) - 140
d = -220
d = 220km

Just want to make sure this is correct.

Thanks
Well, no, you are calculating the distance the boat travels (which has magnitude only, a scalar quantity), not the displacement (which is a vector quantity with magnitude and direction).
The boat travels 140 km north, then does a 180 degree turn and heads back traveling 80 km south. Where does it end up? (Draw a sketch). And welcome to PF! :smile:
 
Okay, so, I'm looking for the distance between the start and the finish.

d = d2-d1
d = 140 - 80
d = 60km [N]

Please tell me that's correct!
 
Yes, the displacement is 60 km [N].:approve:
 
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