Checking Your Work: Calculating Equivalent Resistance

AI Thread Summary
The discussion focuses on calculating the equivalent resistance of a circuit with six 12-ohm resistors. The user outlines their method, combining resistors R5 and R6 in series, then calculating the resulting resistance in parallel with R4, followed by further combinations with R2, R3, and R1. Other participants confirm that the calculations are correct and that the final answer is accurate. Overall, the method used for calculating equivalent resistance is validated by peers. The user successfully verifies their approach to the problem.
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I'm not sure if I'm doing this right, I would appreciate if someone could take a look.

Q. Find the equivalent resistance of the circuit (attached diagram). Each of the six resistors has a resistance equal to 12 ohms.

I'm thinking that R5 and R6 are in series and therefore combine to be 2R.
2R is now in parallel with R4, therefore 1/Req = 1/R + 1/2R = 3/2R

Then 3/2R is in series with R2, so 2R/3 + R = 5R/3

Then 5R/3 is in parallel with R3, so 3/5R + 1/R = 8/5R

And since 8/5R is in series with R1, then 5R/8 + R = 13R/8.

Have I made any major blunders??
 

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I get the same answer. Looks good.
 
Yep, right answer .
 
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