Chemistry Help - Using the Gas Laws

AI Thread Summary
The discussion revolves around calculating the final pressure of an ideal gas when its temperature is increased from 20.0 degrees Celsius to 200.0 degrees Celsius, while keeping the volume constant at 1.00 L. The relevant gas law for this scenario is Guy-Lussac's Law, which relates pressure and temperature. The initial conditions are 1.00 atm and 20.0 degrees Celsius, and the final temperature is 200.0 degrees Celsius. By applying Guy-Lussac's Law, the final pressure can be determined based on the temperature change. This calculation is essential for understanding gas behavior under constant volume conditions.
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Homework Statement



This figure (file attached) shows a container that is sealed at the top by a movable piston. Inside the container is a ideal gas at 1.00 atm, 20.0 degrees Celsius, and 1.00 L.

The gas sample has now returned to its original state of 1.00 atm, 20.0 degrees Celsius and 1.00 L. What will the pressure become if the temperature of the gas is raised to 200.0degrees celsius and the piston is not allowed to move?

Homework Equations



Boyle's Law P_1V_1 = P_2V_2
or
Charles' Law V_1/T_1 = V_2/T_2

The Attempt at a Solution



Okay, in order for the piston not to move, this means that the volume must remain at 1.00 L. What I don't know what to do is how to relate temperature and pressure to solve for the final pressure.
 

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Guy-Lussacs Law P1/T1 = P2/T2
 
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