Child's Displacement on Cubical Jungle Gym: Solving the Problem

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To calculate the child's displacement on a cubical jungle gym, first identify the starting point at the origin (0,0,0) and the endpoint at the opposite corner (2,2,2). The displacement can be broken down into two segments: moving from (0,0,0) to (2,2,0) and then from (2,2,0) to (2,2,2). Using the Pythagorean theorem, the first segment's displacement is √(2² + 2²) = √8, and the second segment's displacement is simply 2m. The total displacement from the origin to the opposite corner is √(2² + 2² + 2²) = √12 or approximately 3.46m.
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I am having problems figuring this out. How should I go about this?


A child starts at one corner of a cubical jungle gym in a playground and climbs up to the diagonally opposite corner. The original corner is the coordinate origin, and the x-, y- and z-axes are oriented along the jungle gym edges. The length of each side is 2m. The child's displacement is?
 
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Break it down into two smaller and easier problems. And draw yourself a diagram! Solve using Pythagoras a² + b² = c²
 
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